比赛 |
20121023 |
评测结果 |
AAAAWWWWWW |
题目名称 |
圆圈舞蹈 |
最终得分 |
40 |
用户昵称 |
青阳 |
运行时间 |
0.043 s |
代码语言 |
C |
内存使用 |
0.60 MiB |
提交时间 |
2012-10-23 20:39:12 |
显示代码纯文本
#include <stdio.h>
#define min(a, b) ((a)<(b)?(a):(b))
int sum[100001];
int main(void)
{
int i, j, t, s;
int n, ans = 0;
int total = 0;
freopen("circlea.in", "r", stdin);
freopen("circlea.out", "w", stdout);
scanf("%d", &n);
for(i = 1; i <= n; i++){
scanf("%d", &t);
sum[i] = sum[i - 1] + t;
total += t;
}
t = s = 0;
i = j = 1;
while(j <= n && i <= n){
s = min(sum[j] - sum[i - 1], total - (sum[j] - sum[i - 1]));
if(s <= t){
if(ans < t){
ans = t;
}
i++;
t = min(sum[j] - sum[i - 1], total - (sum[j] - sum[i - 1]));
}else{
t = s;
j++;
}
}
if(j > n){
j--;
t = min(sum[j] - sum[i - 1], total - (sum[j] - sum[i - 1]));
while(i <= n){
s = min(sum[j] - sum[i - 1], total - (sum[j] - sum[i - 1]));
if(s > t){
t = s;
}else{
break;
}
if(ans < s){
ans = s;
}
i++;
}
}
printf("%d\n", ans);
return 0;
}