多谢前辈%%%

一发AC

注意mod的是2^k不是k

注意算斜率时的数据处理，这有一组数据给的太巧了

∑

回复 @qyd :
发现你了

回复 @王和谐 :
hahahahahahaha

#include<bits/stdc++.h>
using namespace std;
int main()
{
freopen("apple.in","r",stdin);
freopen("apple.out","w",stdout);
long long int n,date=0,ans[10000],i=0;
cin>>n;
while(n>0)
{
date++;
if(n%3==1)
{
i++;
ans[i]=date;
}
n=n-ceil(n*1.0/3);
}
cout<<date<<" "<<ans[1];
fclose(stdin);fclose(stdout);
return 0;
}

我嘞个雷

#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b;
freopen("aplusb.in","r",stdin);
freopen("aplusb.out","w",stdout);
cin>>a>>b;
cout<<a+b;
fclose(stdin);
fclose(stdout);
return 0;
}
这个水体有点儿水

回复 @王和谐 :
hi

#include<bits/stdc++.h>
using namespace std;
int main()
{freopen("csp2022pj_pow.in","r",stdin);
freopen("csp2022pj_pow.out","w",stdout);
int a,b;
cin>>a>>b;
if(pow(a,b)<1000000000) cout<<int(pow(a,b));
else cout<<"-1";
fclose(stdin);fclose(stdout);
return 0;}

666

1

求教程！！！

挺简单

题太水 答案供参考
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s;
int i,n,st,s1=0;
freopen("csp2019pj_number.in","r",stdin);
freopen("csp2019pj_number.out","w",stdout);
getline(cin,s);
st=s.length();
for(i=0;i<=st-1;i++)
if(s[i]=='1') s1++;
if(s1==0) cout<<'0';
else cout<<s1;
fclose(stdin);
fclose(stdout);
}

#include<bits/stdc++.h>
using namespace std;
int main()
{freopen("title.in","r",stdin);
freopen("title.out","w",stdout);
char st[200];int sum;
while(scanf("%s",st)==1) sum+=strlen(st);
cout<<sum;
}