记录编号 |
474178 |
评测结果 |
AAAAAAAAAAAA |
题目名称 |
增强的乘法问题 |
最终得分 |
100 |
用户昵称 |
Cooook |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.068 s |
提交时间 |
2017-11-09 19:25:28 |
内存使用 |
17.29 MiB |
显示代码纯文本
#include <iostream>
#include <cstring>
#include <algorithm>
#include <stdio.h>
#include <math.h>
using std::swap;
#define MAXN 530010
const double PI = acos(-1.0);
char s1[MAXN],s2[MAXN];
int rev[MAXN],N,len,len1,len2,cnt,Ans[MAXN];
template<typename _t>
inline _t read(){
_t x=0,f=1;
char ch=getchar();
for(;ch>'9'||ch<'0';ch=getchar())if(ch=='-')f=-f;
for(;ch>='0'&&ch<='9';ch=getchar())x=x*10+(ch^48);
return x*f;
}
struct Complex{
double x,y;
inline Complex operator + (const Complex & a){return (Complex){x+a.x,y+a.y};}
inline Complex operator - (const Complex & a){return (Complex){x-a.x,y-a.y};}
inline Complex operator * (const Complex & a){return (Complex){x*a.x-y*a.y,x*a.y+y*a.x};}
}a[MAXN],b[MAXN],c[MAXN];
inline void fft(Complex *a,int type){
Complex wn,w,t;
for(int i=0;i<N;i++)if(i<rev[i])swap(a[i],a[rev[i]]);
for(int k=2;k<=N;k<<=1){
wn = (Complex){cos(type*2*PI/k),sin(type*PI*2/k)};
for(int j=0;j<N;j+=k){
w = (Complex){1,0};
for(int i=0;i<(k>>1);i++,w=w*wn)
t=a[i+j+(k>>1)]*w,a[i+j+(k>>1)]=a[i+j]-t,a[i+j]=a[i+j]+t;
}
}
if(type==-1) for(int i=0;i<N;i++) a[i].x/=N;
}
void FFT(Complex *a,Complex *b,int *Ans,int tot){
for(N=1;N<(tot<<1);len++,N<<=1);
for(int i=0;i<N;i++) {
if(i&1)rev[i]=(rev[i>>1]>>1)|(N>>1);
else rev[i]=rev[i>>1]>>1;
}
fft(a,1);fft(b,1);
for(int i=0;i<N;i++) c[i]=a[i]*b[i];fft(c,-1);
for(int i=0;i<N;i++) Ans[i]=round(c[i].x);
}
int main(){
freopen("mul.in","r",stdin);
freopen("mul.out","w",stdout);
scanf("%s%s",s1,s2);
len1=strlen(s1);len2=strlen(s2);
cnt = len1>len2?len1:len2;
for(int i=0;i<len1;i++)a[i].x=s1[len1-i-1]-48;
for(int i=0;i<len2;i++)b[i].x=s2[len2-i-1]-48;
FFT(a,b,Ans,cnt);
for(int i=0;i<N;i++) {
Ans[i+1] += Ans[i] / 10;
Ans[i] %= 10;
}
len = len1+len2;
while(!Ans[len] && len >= 1) --len;
for(int i=len;i>=0;i--)printf("%c",Ans[i]+'0');
return 0;
}