记录编号 |
380627 |
评测结果 |
AAAAAAAAAA |
题目名称 |
QAQ的最短路 |
最终得分 |
100 |
用户昵称 |
kZime |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.051 s |
提交时间 |
2017-03-09 20:15:29 |
内存使用 |
0.48 MiB |
显示代码纯文本
// kZime
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int MX = 103;
const double INF = 1e20;
double f[MX][MX], a[MX][MX];
int n, m;
inline int read() {
int k = 0;
char c = getchar();
for(;!isdigit(c); c = getchar());
for(; isdigit(c); c = getchar())k = k * 10 + c - '0';
return k;
}
int main() {
#ifndef LOCAL
freopen("boboji.in", "r", stdin);
freopen("boboji.out", "w", stdout);
#endif
n = read();
m = read();
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= n; j++) {
if(i != j) {
f[i][j] = f[j][i] = INF;
}
}
}
for(int i = 1; i <= m; i++) {
int x = read();
int y = read();
int z = read();
f[x][y] = f[y][x] = z;
a[x][y] = a[y][x] = 1;
}
for(int k = 1; k <= n; k++) {
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= n; j++) {
if(i != j && i != k && j != k){
if(f[i][j] == f[i][k] + f[k][j]) {
a[i][j] += a[i][k] * a[k][j];
}else if(f[i][j] > f[i][k] + f[k][j]) {
f[i][j] = f[i][k] + f[k][j];
a[i][j] = a[i][k] * a[k][j];
}
}
}
}
}
// for(int i = 1; i <= n; i++) {
// for(int j = 1; j <= n; j++) {
// printf("%.3lf ",a[i][j]);
// }
// printf("\n");
// }
for(int k = 1; k <= n; k++) {
double Iv = 0;
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= n; j++) {
if(f[i][j] == f[i][k] + f[k][j] && i != j && i != k && j != k && a[i][j] > 0){
Iv += a[i][k] * a[k][j] / a[i][j];
}
}
}
printf("%.3lf\n",Iv);
}
return 0;
}