显示代码纯文本
#include<cstdio>
#include<cmath>
#include<iostream>
#include<cstring>
#include<iomanip>
using namespace std;
int N;
double x[70],y[70];
double f[70][70][2]={0};
double dist(int a,int b)
{
a=(a-1)%N+1,b=(b-1)%N+1;
return sqrt((x[a]-x[b])*(x[a]-x[b])+(y[a]-y[b])*(y[a]-y[b]));
}
double DP(int i,int L,bool t)
{
if(L==1) return 0.0;
if(f[i][L][t]) return f[i][L][t];
if(!t) f[i][L][t]=min(dist(i,i+1)+DP(i+1,L-1,0),dist(i+L-1,i)+DP(i+1,L-1,1));
else f[i][L][t]=min(dist(i+L-1,i+L-2)+DP(i,L-1,1),dist(i+L-1,i)+DP(i,L-1,0));
return f[i][L][t];
}
int main()
{
freopen("frogpuzzle.in","r",stdin);
freopen("frogpuzzle.out","w",stdout);
scanf("%d",&N);
for(int i=1;i<=N;i++)
scanf("%lf%lf",&x[i],&y[i]);
double ans=DP(1,N,0);
printf("%.3lf",ans);
return 0;
}