记录编号 |
357774 |
评测结果 |
AAAAAAAAAA |
题目名称 |
[BZOJ 4407] 于神之怒加强版 |
最终得分 |
100 |
用户昵称 |
sxysxy |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
9.226 s |
提交时间 |
2016-12-12 17:41:47 |
内存使用 |
109.99 MiB |
显示代码纯文本
#include <cstdio>
#include <cstring>
#include <cstdarg>
#include <iostream>
#include <queue>
#include <vector>
#include <list>
using namespace std;
#define MAXN 5000001
#define MOD 1000000007
typedef long long LL;
int miu[MAXN];
bool vis[MAXN];
int primes[MAXN/2], tot;
LL pw[MAXN];
LL g[MAXN];
LL pow_mod(LL base, LL exp)
{
LL ans = 1;
for(base %= MOD; exp; base=base*base%MOD, exp >>= 1)
if(exp&1)ans = ans*base%MOD;
return ans;
}
void pre(int n, int k)
{
miu[1] = 1;
pw[1] = g[1] = 1;
for(int i = 2; i <= n; i++)
{
if(!vis[i])
{
primes[tot++] = i;
miu[i] = -1;
pw[i] = pow_mod(i, k);
g[i] = (pw[i]+MOD-1)%MOD;
}
for(int j = 0; j < tot; j++)
{
int k = primes[j]*i;
if(k > n)break;
vis[k] = true;
pw[k] = pw[i]*pw[primes[j]]%MOD;
if(i%primes[j])
{
miu[k] = -miu[i];
g[k] = g[i]*g[primes[j]]%MOD;
}else
{
g[k] = pw[primes[j]]*g[i]%MOD;
break;
}
}
}
for(int i = 2; i <= n; i++)g[i] = (g[i]+g[i-1])%MOD;
}
int main()
{
freopen("bzoj_4407.in", "r", stdin);
freopen("bzoj_4407.out", "w", stdout);
int T, k;
scanf("%d %d", &T, &k);
pre(5000000, k);
while(T--)
{
LL n, m;
scanf("%lld%lld", &n, &m);
LL ans = 0;
if(n > m)swap(n, m);
for(int i = 1, j; i <= n; i = j+1)
{
j = min(n/(n/i), m/(m/i));
ans = (ans+((LL)(n/i)*(LL)(m/i)%MOD)*((g[j]-g[i-1]+MOD)%MOD)%MOD)%MOD;
}
printf("%lld\n", ans);
}
return 0;
}