记录编号 |
326610 |
评测结果 |
TTTTTTTTTT |
题目名称 |
为爱追寻 |
最终得分 |
0 |
用户昵称 |
ciyou |
是否通过 |
未通过 |
代码语言 |
C++ |
运行时间 |
10.008 s |
提交时间 |
2016-10-21 11:03:33 |
内存使用 |
0.31 MiB |
显示代码纯文本
#include<iostream>
#include<cstdio>
#include<vector>
#include<map>
#include<set>
using namespace std;
int n,x,y,xt,yt,ans=1;
struct movement{
int x, y;
bool operator < (const movement& c) const{
if(x>c.x) return true;
if(x<c.x) return false;
else return y>c.y;
}
bool operator = (const movement& c) const{
return x==c.x&&y==c.y;
}
};
set<movement> checked;
movement make(int x,int y){
movement t;
t.x=x;
t.y=y;
return t;
}
int main(){
freopen("loverfinding.in","r",stdin);
freopen("loverfinding.out","w",stdout);
scanf("%d%d%d%d%d",&n,&x,&y,&xt,&yt);
checked.insert(make(x,y));
for(int i=1;i<=n;i++){
int a,b;
scanf("%d%d",&a,&b);
x+=a;
y+=b;
checked.insert(make(x,y));
if(x==xt&&y==yt){
cout<<checked.size();
fclose(stdin);
fclose(stdout);
return 0;
}
}
printf("SingleDogMZX");
fclose(stdin);
fclose(stdout);
return 0;
}