记录编号 |
435212 |
评测结果 |
AAAAAAAAAA |
题目名称 |
[HZOI 2016]简单的AVL树 |
最终得分 |
100 |
用户昵称 |
HeHe |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.002 s |
提交时间 |
2017-08-09 10:58:44 |
内存使用 |
0.31 MiB |
显示代码纯文本
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
typedef unsigned long long LL;
inline void Pow(LL x);
LL N, p;
LL res[3][3] = {{1, 0, 0},
{0, 1, 0},
{0, 0, 1}};
LL P[3][3] = {{0, 1, 0},
{1, 1, 0},
{0, 1, 1}};
LL ans[1][3] = {0, 1, 1};
LL temp[3][3];
int main() {
#ifndef LOCAL
freopen("AVL.in", "r", stdin);
freopen("AVL.out", "w", stdout);
#endif
scanf("%lld%lld", &N, &p);
//for(LL i = 2; i <= N; ++i) {
// tmp = pre;
// pre = now;
// now = now % p + tmp % p + 1;
//}
Pow(N);
memset(temp, 0x00, sizeof(temp));
for(char i = 0; i < 1; ++i)
for(char j = 0; j < 3; ++j)
for(char k = 0; k < 3; ++k)
(temp[i][j] += ans[i][k] * res[k][j]) %= p;
printf("%lld", temp[0][0]);
return 0;
}
inline void Pow(LL x) {
while(x) {
if(x & 1) {
memset(temp, 0x00, sizeof(temp));
for(char i = 0; i < 3; ++i)
for(char j = 0; j < 3; ++j)
for(char k = 0; k < 3; ++k)
(temp[i][j] += res[i][k] * P[k][j]) %= p;
for(char i = 0; i < 3; ++i)
for(char j = 0; j < 3; ++j)
res[i][j] = temp[i][j];
}
memset(temp, 0x00, sizeof(temp));
for(char i = 0; i < 3; ++i)
for(char j = 0; j < 3; ++j)
for(char k = 0; k < 3; ++k)
(temp[i][j] += P[i][k] * P[k][j]) %= p;
for(char i = 0; i < 3; ++i)
for(char j = 0; j < 3; ++j)
P[i][j] = temp[i][j];
x >>= 1;
}
return ;
}