记录编号 |
587510 |
评测结果 |
AAAAA |
题目名称 |
平方前缀和 |
最终得分 |
100 |
用户昵称 |
┭┮﹏┭┮ |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
1.596 s |
提交时间 |
2024-04-04 00:06:57 |
内存使用 |
67.72 MiB |
显示代码纯文本
#include <bits/stdc++.h>
using namespace std;
//杜教筛
#define ll long long
const int N = 5e6+10;
const ll mod = 1e9+7,inv6 = 166666668,inv2 = 500000004,m = 5e6;
ll n;
int p[N],cnt;
ll f[N];
bool v[N];
unordered_map<ll,ll>sumf;
void get(){
f[1] = 1;
for(int i = 2;i <= m;i++){
if(!v[i])p[++cnt] = i,f[i] = i - 1;
for(int j = 1;j <= cnt && i <= m / p[j];j++){
v[i*p[j]] = 1;
if(i % p[j] == 0){
f[i*p[j]] = f[i] * (ll)p[j] % mod;break;
}
f[i*p[j]] = f[i] * (ll)(p[j] - 1) % mod;
}
}
for(int i = 1;i <= m;i++)f[i] = (f[i] * (ll)i % mod + f[i-1]) % mod;
}
ll s(ll l,ll r){
return ((l + r) * (r - l + 1ll) / 2ll) % mod;
}
ll S(ll x){
if(x <= m)return f[x];
if(sumf[x])return sumf[x];
ll sum = (((x + 1) * (2ll * x + 1ll)) % (mod * 6) * x / 6) % mod;//??
for(ll l = 2ll,r;l <= x;l = r + 1ll){
r = min(x,x / (x / l));
sum = ((sum - (s(l,r) * S(x / l) % mod)) % mod + mod) % mod;
}
return sumf[x] = sum;
}
int main(){
freopen("squaresum.in","r",stdin);
freopen("squaresum.out","w",stdout);
get();
scanf("%lld",&n);//(φ・id) * id = id ^ 2
printf("%lld\n",S(n));
return 0;
}