记录编号 |
325733 |
评测结果 |
AAAAAAAAA |
题目名称 |
[USACO 4.2] 完美的牛栏 |
最终得分 |
100 |
用户昵称 |
sxysxy |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.018 s |
提交时间 |
2016-10-20 11:10:03 |
内存使用 |
0.27 MiB |
显示代码纯文本
- #include <cstdio>
- #include <cstdlib>
- #include <cstring>
- #include <string>
- #include <list>
- #include <vector>
- #include <queue>
- #include <map>
- using namespace std;
- #define MAXN 402
- class dinic
- {
- private:
- bool vis[MAXN];
- int dist[MAXN];
- int cure[MAXN];
- vector<int> G[MAXN];
- struct edge
- {
- int from, to, rem;
- };
- int s, t;
- vector<edge> edges;
- public:
- dinic(int fr, int to)
- {
- s = fr;
- t = to;
- }
- void addedge(int u, int v, int c)
- {
- edges.push_back((edge){u, v, c});
- edges.push_back((edge){v, u, 0});
- int k = edges.size();
- G[u].push_back(k-2);
- G[v].push_back(k-1);
- }
- bool bfs()
- {
- memset(vis, 0, sizeof(vis));
- queue<int> q;
- q.push(s);
- vis[s] = true;
- dist[s] = 0;
- while(q.size())
- {
- int c = q.front();
- q.pop();
- for(int i = 0; i < G[c].size(); i++)
- {
- edge &e = edges[G[c][i]];
- if(!vis[e.to] && e.rem > 0)
- {
- vis[e.to] = true;
- dist[e.to] = dist[c] + 1;
- q.push(e.to);
- }
- }
- }
- return vis[t];
- }
- int dfs(int x, int f)
- {
- if(f == 0 || x == t)return f;
- int tot = 0;
- int nt;
- for(int &i = cure[x]; i < G[x].size(); i++)
- {
- edge &e = edges[G[x][i]];
- if(dist[e.to] == dist[x] + 1 && (nt = dfs(e.to, min(f, e.rem))) > 0)
- {
- f -= nt;
- tot += nt;
- e.rem -= nt;
- edges[G[x][i]^1].rem += nt;
- if(f == 0)break;
- }
- }
- return tot;
- }
- int maxf()
- {
- int f = 0;
- while(bfs())
- {
- memset(cure, 0, sizeof(cure));
- f += dfs(s, 0x7fffffff);
- }
- return f;
- }
- };
-
- int main()
- {
- freopen("stall4.in", "r", stdin);
- freopen("stall4.out", "w", stdout);
- int n, m;
- scanf("%d %d", &n, &m);
- dinic d(0, n+m+1);
- for(int i = 1; i <= n; i++)
- {
- int k, t;
- scanf("%d", &k);
- while(k--)
- {
- scanf("%d", &t);
- d.addedge(i, n+t, 1);
- }
- }
- for(int i = 1; i <= n; i++)
- d.addedge(0, i, 1);
- for(int i = 1; i <= m; i++)
- d.addedge(n+i, n+m+1, 1);
- printf("%d\n", d.maxf());
- return 0;
- }