记录编号 |
571122 |
评测结果 |
AAAAAAAAAA |
题目名称 |
[BZOJ 2820] YY的GCD |
最终得分 |
100 |
用户昵称 |
lihaoze |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
9.530 s |
提交时间 |
2022-05-08 13:59:09 |
内存使用 |
129.71 MiB |
显示代码纯文本
#include <bits/stdc++.h>
#define OPEN(_x) freopen(#_x".in", "r", stdin); freopen(#_x".out", "w", stdout)
#define rep(_x, _y, _z) for (int _x = (_y); _x <= _z; ++ _x)
#define rep1(_x, _y, _z, _a) for (int _x = (_y); _x <= _z; _x += _a)
namespace IO {
inline int read() {
char ch = getchar();
int ret = 0, sig = 1;
while(ch < '0' || ch > '9') { if(ch == '-') sig = -1; ch = getchar(); }
while(ch >= '0' && ch <= '9') ret *= 10, ret += ch - 48, ch = getchar();
return ret * sig;
}
};
using IO::read;
using i64 = long long;
const int N = 1e7+10;
int primes[N], mu[N], s[N], cnt, t;
bool st[N];
void get_mu() {
mu[1] = st[1] = 1;
rep (i, 2, N) {
if (!st[i]) primes[++ cnt] = i, mu[i] = -1;
rep (j, 1, cnt && primes[j] <= N / i) {
st[i * primes[j]] = true;
if (i % primes[j] == 0) {
mu[i * primes[j]] = 0;
break;
}
mu[i * primes[j]] = - mu[i];
}
}
}
i64 calc(int n, int m) {
i64 res = 0;
int l = 1, r;
while (l <= std::min(n, m)) {
r = std::min(n / (n / l), m / (m / l));
res += 1LL * (s[r] - s[l - 1]) * (n / l) * (m / l);
l = r + 1;
}
return res;
}
void init() {
get_mu();
rep (i, 1, cnt)
rep1(j, primes[i], N, primes[i])
s[j] += mu[j / primes[i]];
rep (i, 2, N) s[i] += s[i - 1];
}
int main() {
OPEN(YYnoGCD);
init();
t = read();
while (t --) {
int n = read(), m = read();
printf("%lld\n", calc(n, m));
}
return 0;
}