记录编号 |
321776 |
评测结果 |
AAAAAAAAAA |
题目名称 |
线型网络 |
最终得分 |
100 |
用户昵称 |
Tabing010102 |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.853 s |
提交时间 |
2016-10-13 21:38:56 |
内存使用 |
0.29 MiB |
显示代码纯文本
- #include <cstdio>
- #include <ctime>
- #include <cmath>
- #include <algorithm>
- #include <cstdlib>
- using namespace std;
- const int maxn = 20+5;
- const double INF = 1e7;
- FILE *fin, *fout;
- int n, orders[maxn];
- int p[maxn][2];
- double d[maxn][maxn];
- double ans = INF;
- inline double dis(int a, int b) {
- return sqrt((p[a][0] - p[b][0])*(p[a][0] - p[b][0]) + (p[a][1] - p[b][1])*(p[a][1] - p[b][1]));
- }
- inline double min(double a, double b) { return a<b?a:b; }
- void reserve(int L, int R) {
- while(L < R) {
- swap(orders[L], orders[R]);
- L++; R--;
- }
- }
- int main() {
- srand(time(NULL));
- fin = fopen("linec.in", "r");
- fout = fopen("linec.out", "w");
- // fout = stdout;
- fscanf(fin ,"%d", &n);
- for(int i = 0; i < n; i++) { fscanf(fin, "%d%d", &p[i][0], &p[i][1]); orders[i]=i; }
- for(int i = 0; i < n; i++) for(int j = 0; j < n; j++) {
- d[i][j] = dis(i, j);
- // fprintf(fout, "d[i=%d][j=%d] = %.2lf\n", i, j, d[i][j]);
- }
- for(int i = 1; i <= 10000; i++) {//随机化次数
- // for(int j = 0; j < n; j++) fprintf(fout, "%d ", orders[j]);
- // fprintf(fout, "\n");
- //随机化
- for(int j = 1; j <= 100; j++) swap(orders[rand()%n], orders[rand()%n]);
- //贪心
- for(int a = 1; a < n; a++) for(int b = a; b < n-1; b++)
- if(d[orders[a]][orders[a-1]]+d[orders[b]][orders[b+1]] > d[orders[a-1]][orders[b]]+d[orders[a]][orders[b+1]])
- reserve(a, b);
- // for(int j = 0; j < n; j++) fprintf(fout, "%d ", orders[j]);
- double tmp = 0;
- for(int j = 0; j < n-1; j++) tmp += d[orders[j]][orders[j+1]];
- // fprintf(fout, "%.2lf\n", tmp);
- ans = min(ans, tmp);
- }
- fprintf(fout, "%.2lf\n", ans);
- return 0;
- }