记录编号	387895	评测结果	AAAAAAAAAA
题目名称	数列操作ψ	最终得分	100
用户昵称	DaD3zZ	是否通过	通过
代码语言	C++	运行时间	1.907 s
提交时间	2017-03-27 20:15:15	内存使用	9.85 MiB

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
using namespace std;
inline int read()
{
	int x=0,f=1; char ch=getchar();
	while (ch<'0' || ch>'9') {if (ch=='-') f=-1; ch=getchar();}
	while (ch>='0' && ch<='9') {x=x*10+ch-'0'; ch=getchar();}
	return x*f;
}

#define MAXN 100010

int N,M,a[MAXN];

#define AllSame ((1<<30)-1)

struct SgtNode{
	int l,r,otag,atag,same,maxx;
}tree[MAXN<<2];

inline void Update(const int &now) 
{
	tree[now].maxx=max(tree[now<<1].maxx,tree[now<<1|1].maxx);
	tree[now].same=( tree[now<<1].same & tree[now<<1|1].same ) & ( tree[now<<1].maxx ^ (~tree[now<<1|1].maxx) );
}

inline void Build(const int &now,const int &l,const int &r)
{
	tree[now].l=l; tree[now].r=r;
	tree[now].otag=0; tree[now].atag=AllSame;
	if (l==r) {
		tree[now].maxx=a[l]; tree[now].same=AllSame;
		return;
	}
	int mid=(l+r)>>1;
	Build(now<<1,l,mid); Build(now<<1|1,mid+1,r);
	Update(now);
}

inline void And(const int &now,const int &val) {tree[now].maxx&=val; tree[now].otag&=val; tree[now].atag&=val;}

inline void Or(const int &now,const int &val) {tree[now].maxx|=val; tree[now].otag|=val; tree[now].atag|=val;}

inline void Pushdown(const int &now)
{
	if (tree[now].l==tree[now].r || (!tree[now].otag && tree[now].atag==AllSame)) return;
	int ot=tree[now].otag,at=tree[now].atag;
	tree[now].otag=0; tree[now].atag=AllSame;
	if (ot) Or(now<<1,ot),Or(now<<1|1,ot);
	if (at!=AllSame) And(now<<1,at),And(now<<1|1,at);
}

inline bool CheckOr(const int &same,const int &val) {return (same&val)==val;}

inline void ModifyOr(const int &now,const int &L,const int &R,const int &val)
{
	int l=tree[now].l,r=tree[now].r;
	if (L>r || R<l) return;
	if (L<=l && R>=r && CheckOr(tree[now].same,val)) {
		Or(now,val);
		return;
	}
	Pushdown(now);
	ModifyOr(now<<1,L,R,val);
	ModifyOr(now<<1|1,L,R,val);
	Update(now);
}

inline bool CheckAnd(const int &same,const int &val) {return (~same&AllSame|val)==val;}

inline void ModifyAnd(const int &now,const int &L,const int &R,const int &val)
{
	int l=tree[now].l,r=tree[now].r;
	if (L>r || R<l) return;
	if (L<=l && R>=r && CheckAnd(tree[now].same,val)) {
		And(now,val);
		return;
	}
	Pushdown(now);
	ModifyAnd(now<<1,L,R,val);
	ModifyAnd(now<<1|1,L,R,val);
	Update(now);
}

inline int Query(const int &now,const int &L,const int &R)
{
	int l=tree[now].l,r=tree[now].r;
	if (L<=l && R>=r) {
		return tree[now].maxx;
	}
	Pushdown(now);
	int mid=(l+r)>>1,re=0;
	if (L<=mid) re=Query(now<<1,L,R);
	if (R>mid) re=max(re,Query(now<<1|1,L,R));
	return re;
}

int main()
{
	freopen("series_wei.in","r",stdin);
	freopen("series_wei.out","w",stdout);
	
	N=read(),M=read();
	for (int i=1; i<=N; i++) a[i]=read();
	Build(1,1,N);
	while (M--) {
		int opt=read(),l=read(),r=read(),val;
		switch (opt) {
			case 1: val=read(); ModifyAnd(1,l,r,val); break;
			case 2: val=read(); ModifyOr(1,l,r,val); break;
			case 3: printf("%d\n",Query(1,l,r)); break;
		}
	}
	return 0;
}
/*
8 6
4 0 5 7 2 9 12 8
2 2 5 15
1 3 5 2
3 5 7
1 5 7 12
2 1 6 4
3 2 6
*/