记录编号 |
193383 |
评测结果 |
AAAAAAAAAA |
题目名称 |
神奇宝贝大师 |
最终得分 |
100 |
用户昵称 |
devil |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.079 s |
提交时间 |
2015-10-14 18:14:10 |
内存使用 |
38.62 MiB |
显示代码纯文本
#include <cstdlib>
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <map>
#include <stack>
#include <vector>
#include <map>
#include <queue>
#include <ctime>
#include <algorithm>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef unsigned int uint;
const int inf=1061109567;
const int maxn=200;
const int maxm=10000010;
const int mod=10000007;
map<string,int> num;
int v[maxn],val[maxn];
int p[maxn];
int d[maxn][maxn];
int f[maxm];
int vis[maxn],dir[maxn];
int Swap(int &a,int &b) {int t=a;a=b;b=t;}
int found(int x) {return (p[x]==x)?x:p[x]=found(p[x]);}
int main()
{
freopen("pokemonmaster.in","r",stdin);
freopen("pokemonmaster.out","w",stdout);
//clock_t st=clock();
memset(d,0x3f,sizeof(d));
string name1,name2;
int n1,n2;
int n;scanf("%d",&n);
for(int i=1;i<=n;i++)
{
cin>>name1;
num[name1]=i;
scanf("%d",&v[i]);
p[i]=i;
}
int m;scanf("%d",&m);
for(int i=1;i<=m;i++)
{
cin>>name1>>name2;
n1=found(num[name1]);
n2=found(num[name2]);
if(n1!=n2)
{
p[n1]=n2;
}
}
int cnt=1;
for(int i=1;i<=n;i++)
{
int t=found(i);
if(!vis[t])
{
vis[t]=1;
dir[t]=cnt++;
}
}
for(int i=1;i<=n;i++) val[dir[found(i)]]+=v[i];
cnt--;
scanf("%d",&m);
for(int i=1;i<=m;i++)
{
cin>>name1>>name2;
n1=dir[found(num[name1])];
n2=dir[found(num[name2])];
scanf("%d",&d[n1][n2]);
d[n2][n1]=d[n1][n2];
}
for(int k=1;k<=cnt;k++)
{
for(int i=1;i<=cnt;i++)
{
for(int j=1;j<=cnt;j++)
{
if(d[i][j]>d[i][k]+d[k][j])
d[i][j]=d[i][k]+d[k][j];
}
}
}
int money;cin>>name1;n1=dir[found(num[name1])];
scanf("%d",&money);
for(int i=1;i<=cnt;i++)
{
if(i==n1||d[i][n1]==inf) continue;
for(int j=money;j>=d[i][n1];j--)
f[j]=max(f[j],f[j-d[i][n1]]+val[i]);
}
printf("%d\n",f[money]%mod);
int q;scanf("%d",&q);
while(q--)
{
cin>>name1>>name2;
n1=dir[found(num[name1])];
n2=dir[found(num[name2])];
if(d[n1][n2]!=inf) printf("%d\n",d[n1][n2]);
else printf("-1\n");
}
//clock_t ed=clock();
//printf("\nTime used : %.5lf Ms\n",double(ed-st)/CLOCKS_PER_SEC);
return 0;
}