记录编号 |
471037 |
评测结果 |
AAAAAAAAAA |
题目名称 |
[福州培训2010] 最大和 |
最终得分 |
100 |
用户昵称 |
HeHe |
是否通过 |
通过 |
代码语言 |
C++ |
运行时间 |
0.404 s |
提交时间 |
2017-11-05 19:54:32 |
内存使用 |
1.33 MiB |
显示代码纯文本
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
inline char getc(void) {
static char buf[1 << 18], *fs, *ft;
return (fs == ft && (ft = (fs = buf) + fread(buf, 1, 1 << 18, stdin)), fs == ft) ? EOF : *fs++;
}
inline int read(void) {
char tmp = getc(), f = 1;
int res = 0;
while(!isgraph(tmp)) tmp = getc();
if(tmp == '-') f = -1, tmp = getc();
while(isdigit(tmp))
res = ((res + (res << 2)) << 1) + (tmp ^ 0x30),
tmp = getc();
return res * f;
}
#ifndef LOCAL
# define MAXN (100010)
#else
# define MAXN (1000)
#endif
int s[MAXN << 1];
int N, n;
int l, r, sum, mx;
int main() {
#ifndef LOCAL
freopen("maxsum.in", "r", stdin);
freopen("maxsum.out", "w", stdout);
#endif
n = (N = read()) << 1;
for(int i = 1; i <= N; ++i)
s[i] = s[i + N] = read();
l = r = 1;
for(; r <= n; ++r) {
if(r - l == N) sum -= s[l], r = ++l, sum = 0;
sum += s[r];
if(sum < 0) l = r + 1, sum = 0;
mx = max(mx, sum);
}
printf("%d\n", mx);
return 0;
}