记录编号	599113	评测结果	AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
题目名称	[SYOI 2018] 简单的线段树	最终得分	100
用户昵称	LikableP	是否通过	通过
代码语言	C++	运行时间	13.559 s
提交时间	2025-02-28 19:09:15	内存使用	5.97 MiB

#pragma GCC optimize(2) 
#include <iostream>
#include <cstdio>
#include <fstream>
#define ls(root) root << 1
#define rs(root) root << 1 | 1
#define Merge(root) tree[root] = (tree[ls(root)] + tree[rs(root)]) % p;
using namespace std;
typedef long long ll;
 
const int MAXN = 1e5;
 
int n, m, p;
ll a[MAXN + 10];
 
ll tree[(MAXN << 2) + 10], lazya[(MAXN << 2) + 10], lazym[(MAXN << 2) + 10];
void Build(int root, int lt, int rt) {
	lazym[root] = 1;
	if (lt == rt) return ;
	int mid = lt + ((rt - lt) >> 1);
	Build(ls(root), lt, mid);
	Build(rs(root), mid + 1, rt);
	return ;
}
 
void PushDown(int root, int lt, int rt) {
	if (lazya[root] == 0 && lazym[root] == 1) return ;
	(tree[ls(root)] *= lazym[root]) %= p;
	(lazym[ls(root)] *= lazym[root]) %= p;
	(lazya[ls(root)] *= lazym[root]) %= p;
	(tree[rs(root)] *= lazym[root]) %= p;
	(lazym[rs(root)] *= lazym[root]) %= p;
	(lazya[rs(root)] *= lazym[root]) %= p;
	lazym[root] = 1;
	int mid = lt + ((rt - lt) >> 1);
	(tree[ls(root)] += (mid - lt + 1) * 1ll * lazya[root]) %= p;
	(lazya[ls(root)] += lazya[root]) %= p;
	(tree[rs(root)] += (rt - mid) * 1ll * lazya[root]) %= p;
	(lazya[rs(root)] += lazya[root]) %= p;
	lazya[root] = 0;
	return ;
}
 
ll GetSeq(int root, int lt, int rt, int lq, int rq) {
	if (lt == lq && rt == rq) {
		return tree[root];
	}
	PushDown(root, lt, rt);
	int mid = lt + ((rt - lt) >> 1);
	if (rq <= mid) {
		return GetSeq(ls(root), lt, mid, lq, rq);
	} else if (lq > mid) {
		return GetSeq(rs(root), mid + 1, rt, lq, rq);
	} else {
		return GetSeq(ls(root), lt, mid, lq, mid) + GetSeq(rs(root), mid + 1, rt, mid + 1, rq);
	}
}
 
void AddSeq(int root, int lt, int rt, int lq, int rq, int val) {
	if (lt == lq && rt == rq) {
		(tree[root] += (rt - lt + 1) * 1ll * val) %= p;
		(lazya[root] += val) %= p;
		return ;
	}
	PushDown(root, lt, rt);
	int mid = lt + ((rt - lt) >> 1);
	if (rq <= mid) {
		AddSeq(ls(root), lt, mid, lq, rq, val);
	} else if (lq > mid) {
		AddSeq(rs(root), mid + 1, rt, lq, rq, val);
	} else {
		AddSeq(ls(root), lt, mid, lq, mid, val);
		AddSeq(rs(root), mid + 1, rt, mid + 1, rq, val);
	}
	Merge(root);
	return ;
}
 
void MulSeq(int root, int lt, int rt, int lq, int rq, int val) {
	if (lt == lq && rt == rq) {
		(tree[root] *= val) %= p;
		(lazya[root] *= val) %= p;
		(lazym[root] *= val) %= p;
		return ;
	}
	PushDown(root, lt, rt);
	int mid = lt + ((rt - lt) >> 1);
	if (rq <= mid) {
		MulSeq(ls(root), lt, mid, lq, rq, val);
	} else if (lq > mid) {
		MulSeq(rs(root), mid + 1, rt, lq, rq, val);
	} else {
		MulSeq(ls(root), lt, mid, lq, mid, val);
		MulSeq(rs(root), mid + 1, rt, mid + 1, rq, val);
	}
	Merge(root);
	return ;
}
 
int main() {
	freopen("easilysegmenttree.in", "r", stdin);
	freopen("easilysegmenttree.out", "w", stdout);
	scanf("%d %d %d", &n, &m, &p);
	Build(1, 1, n);
	while (m--) {
		int op, l, r, v;
		scanf("%d %d %d", &op, &l, &r);
		if (op == 1) {
			scanf("%d", &v);
			AddSeq(1, 1, n, l, r, v);
		} else if (op == 2) {
			scanf("%d", &v);
			MulSeq(1, 1, n, l, r, v);
		} else if (op == 3) {
			printf("%lld\n", GetSeq(1, 1, n, l, r) % p);
		} else {
			printf("QwQ");
		}
	}
	return 0;
}