记录编号 |
19992 |
评测结果 |
AAAAAAAAAA |
题目名称 |
罪犯问题B |
最终得分 |
100 |
用户昵称 |
belong.zmx |
是否通过 |
通过 |
代码语言 |
Pascal |
运行时间 |
0.152 s |
提交时间 |
2010-10-19 18:32:15 |
内存使用 |
0.31 MiB |
显示代码纯文本
program criminalb(input,output);
var
n,m,k:longint;
evil:array[1..1000]of integer;
a:array[1..1000,1..2]of integer;
f:array[0..50000]of longint;
i,j,max,x,t:longint;
function min(x,y:longint):longint;
begin
if x>y then min:=y else min:=x;
end;
begin
assign(input,'criminalb.in');
reset(input);
readln(n,m,k);
for i:=1 to n do
begin
read(evil[i]);
max:=max+evil[i];
end;
readln;
for i:=1 to m do
begin
readln(x);
if x>0 then inc(a[x,1]);
if x<0 then inc(a[-x,2]);
end;
close(input);
for i:=1 to n do
begin
x:=min(a[i,1],a[i,2]);
a[i,1]:=a[i,1]-x;
a[i,2]:=a[i,2]-x;
k:=k-x;
end;
assign(output,'criminalb.out');
rewrite(output);
for i:=1 to n do
for j:=k downto a[i,2] do
begin
if f[j-a[i,2]]+evil[i]>f[j] then f[j]:=f[j-a[i,2]]+evil[i];
end;
writeln(f[k]);
for i:=0 to k do f[i]:=0;
for i:=1 to n do
for j:=k downto a[i,1] do
begin
if f[j-a[i,1]]+evil[i]>f[j] then f[j]:=f[j-a[i,1]]+evil[i];
end;
writeln(max-f[k]);
close(output);
end.