| 记录编号 | 
        36798 | 
        评测结果 | 
        AAAAAAAAA | 
    
    
        | 题目名称 | 
        495.[POJ 2823]滑动窗口 | 
        最终得分 | 
        100 | 
            
    
    
        | 用户昵称 | 
         kaaala | 
        是否通过 | 
        通过 | 
    
    
        | 代码语言 | 
        C++ | 
        运行时间 | 
        1.931 s  | 
    
    
        | 提交时间 | 
        2012-03-19 21:01:52 | 
        内存使用 | 
        4.08 MiB  | 
        
    
    
    
    		显示代码纯文本
		
		#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cmath>
#include<cstring>
#include<algorithm>
#include<deque>
using namespace std;
int N,K,A[1000010];
deque<int>deq;
int main()
{
	freopen("window.in","r",stdin);
	freopen("window.out","w",stdout);
	scanf("%d%d",&N,&K);
	for(int i=1;i<=N;i++)
		scanf("%d",&A[i]);
	for(int i=1;i<=N;i++)
	{
		while(!deq.empty()&&A[i]<=A[deq.back()])
			deq.pop_back();
		deq.push_back(i);
		if(i-deq.front()>=K)
			deq.pop_front();
		if(i>=K)
			printf("%d ",A[deq.front()]);
	}
	printf("\n");
	deq.clear();
	for(int i=1;i<=N;i++)
	{
		while(!deq.empty()&&A[i]>=A[deq.back()])
			deq.pop_back();
		deq.push_back(i);
		if(i-deq.front()>=K)
			deq.pop_front();
		if(i>=K)
			printf("%d ",A[deq.front()]);
	}
	printf("\n");
	return 0;
}