| 记录编号 |
611345 |
评测结果 |
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA |
| 题目名称 |
[THUPC 2025 Final] 图,距离,最优化 |
最终得分 |
100 |
| 用户昵称 |
LikableP |
是否通过 |
通过 |
| 代码语言 |
C++ |
运行时间 |
24.061 s |
| 提交时间 |
2026-01-28 12:26:33 |
内存使用 |
12.81 MiB |
显示代码纯文本
#include<bits/stdc++.h>
using namespace std;
#define ll long long
const int _ = 6e5 + 7;
ll dp[_], tmp[_], x[_], sumx[_]; int T, N;
int main(){
freopen("thupc2025_gradistoptimiz.in", "r", stdin);
freopen("thupc2025_gradistoptimiz.out", "w", stdout);
cin >> T;
for(int _ = 1 ; _ <= T ; ++_){
cin >> N; for(int i = 1 ; i <= N ; ++i) cin >> x[i];
sort(x + 1, x + N + 1);
for(int i = 1 ; i <= N ; ++i) sumx[i] = sumx[i - 1] + x[i];
memset(dp, -0x3f, sizeof(dp)); dp[0] = 0;
for(int i = N ; i > 1 ; --i){
memset(tmp, -0x3f, sizeof(tmp));
for(int j = 0 ; j <= sumx[N] - sumx[i] ; ++j)
if(dp[j] != tmp[_ - 1]){
tmp[j] = max(tmp[j], dp[j] + (sumx[N] - sumx[i - 1] - j) * (sumx[i - 1] + j));
tmp[j + x[i]] = max(tmp[j + x[i]], dp[j] + (j + x[i]) * (sumx[N] - j - x[i]));
}
memcpy(dp, tmp, sizeof(dp));
}
ll mx = 0; for(int i = 0 ; i <= sumx[N] ; ++i) mx = max(mx, dp[i]);
cout << mx << endl;
}
return 0;
}